For an increase in the difference between P_A | vedclass

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(C) The difference between $P_A^0$ and $P_A$ is the lowering of vapor pressure,which is given by $\Delta P = P_A^0 - P_A = P_A^0 X_B$.An increase in t

Vedclass · Accepted Answer

Boiling point increases,freezing point decreases

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(C) The difference between $P_A^0$ and $P_A$ is the lowering of vapor pressure,which is given by $\Delta P = P_A^0 - P_A = P_A^0 X_B$.An increase in this difference implies an increase in the mole fraction of the solute $(X_B)$,which means the concentration of the solute increases.According to the colligative properties:$1$. Elevation in boiling point: $\Delta T_b = K_b 	imes m$. As the concentration $(m)$ increases,$\Delta T_b$ increases,so the boiling point increases.$2$. Depression in freezing point: $\Delta T_f = K_f 	imes m$. As the concentration $(m)$ increases,$\Delta T_f$ increases,which means the freezing point decreases.

For an increase in the difference between $P_A^0$ and $P_A$,which of the following occurs?

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